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web host reseller web host reseller But , so the following code is valid as well: public void someMethod(Number n){ // method body omitted } someMethod(new Integer(10)); // OK someMethod(new Double(10.1)); // OK The same is also true with generics. You can perform a generic type invocation, passing as its type argument, and any subsequent invocation of will be allowed if the argument is compatible with : Box<Number> box = new Box<Number>(); box.add(new Integer(10)); // OK box.add(new Double(10.

web host reseller 1)); // OK Now consider the following method: public void boxTest(Box<Number> n){ // method body omitted } What type of argument does it accept? By looking at its signature, we can see that it accepts a single argument whose type is . But what exactly does that mean? Are you allowed to pass in , as you might expect? Surprisingly, the answer is "no", because . Understanding why becomes much easier if you think of tangible objects — things you can actually picture — such as a cage: // A cage is a collection of things, with bars to keep them in. interface Cage<E> extends Collection<E>; The interface is the root interface of the ; it represents a group of objects. Since a cage would be used for holding a collection of objects (the animals), it makes sense to include it in this example.

web host reseller A lion is a kind of animal, so would be a subtype of : interface Lion extends Animal {} Lion king = ...; Where we need some animal, we're free to provide a lion: Animal a = king; A lion can of course be put into a lion cage: Cage<Lion> lionCage = ..

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